
JamesMan |

Does a huge creature with all of the shikigami style feats deal damage as if three sizes larger, or is the damage capped at two sizes larger because there is no size bigger than colossal in pathfinder rules?*
*I assume theres nothing bigger than colossal in pathfinder anyway?
I'm trying to find something official on this or as close to it because I'm stumped.

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Size Changes, Effective Size Changes, and Damage Dice Progression FAQ
When the damage dealt by a creature’s weapons or natural attacks changes due to a change in its size (or the size of its weapon), use the following rules to determine the new damage.
• If the size increases by one step, look up the original damage on the chart and increase the damage by two steps. If the initial size is Small or lower (or is treated as Small or lower) or the initial damage is 1d6 or less, instead increase the damage by one step.
• If the size decreases by one step, look up the original damage on the chart and decrease the damage by two steps. If the initial size is Medium or lower (or is treated as Medium or lower) or the initial damage is 1d8 or less, instead decrease the damage by one step.
• If the exact number of original dice is not found on this chart, apply the following before adjusting the damage dice. If the damage is a number of d6, find the next lowest number of d6 on the chart and use that number of d8 as the original damage value (for example, 10d6 would instead be treated as 8d8). If the damage is a number of d8, find the next highest number of d8 on the chart and use that number of d6 as the original damage value (for example, 5d8 would instead be treated as 6d6). Once you have the new damage value, adjust by the number of steps noted above.
• If the die type is not referenced on this chart, apply the following rules before adjusting the damage dice. 2d4 counts as 1d8 on the chart, 3d4 counts as 2d6 on the chart, and so on for higher numbers of d4. 1d12 counts as 2d6 on the chart, and so on for higher numbers of d12.
• Finally, 2d10 increases to 4d8 and decreases to 2d8, regardless of the initial size, and so on for higher numbers of d10.
Damage Dice Progression Chart
1
1d2
1d3
1d4
1d6
1d8
1d10
2d6
2d8
3d6
3d8
4d6
4d8
6d6
6d8
8d6
8d8
12d6
12d8
16d6
Pretty sure its commonly assumed you can go beyond 16 dice, but that might just be Greater Vital Strike coloring my memory.

JamesMan |

Size Changes, Effective Size Changes, and Damage Dice Progression FAQ** spoiler omitted **...
Isn't that just about how the die size changes numerically? It doesnt address the possibility of an actual or theoretical size above colossal at all. It doesnt even feature the word colossal in the entire FAQ. I dont think this helps me answer my question.
Im well aware of how the die would increase IF its possible to have a weapon treated as a size category that doesnt exist, but im trying to determine if theoretical sizes above colossal actually exist in the rules or if the damage is capped when it reaches maximum pathfinder size (colossal).
The best i can find is that the size categories have predetermined measurement ranges associated with them, except colossal which is simply "64ft+" which means there is no size above colossal in practicality or theory. So that would probably mean the damage should cap as being treated as colossal, but is there something to overrule that?

ErichAD |

The Mourning One Is the only one I can find quickly. There are plenty that have apparent size boosts to their weapon damage that are unaccounted for.

JamesMan |

The Mourning One Is the only one I can find quickly. There are plenty that have apparent size boosts to their weapon damage that are unaccounted for.
Yeah, i found that one too but i cant find any others so i'd like to confirm that isn't an isolated error. (As bestiaries are well known for having many small mistakes)
Im aware that there are "plenty" others which deviate from the average damage dice, but that's normal for monsters and is no way indicative of being treated as a size category bigger than exists in the game.
If anyone could provide another example of a colossal creature having the improved natural attack feat or an ability that specifically references a colossal creature as being x size categories bigger I'd be content.
I found under a dragon's bite attack:
A dragon's bite attack has reach as if the creature were one size category larger (+10 feet for Colossal dragons).
But im not sure if bolded is clarification because the size category larger than colossal isn't listed, or extra rules because a size category larger than colossal isn't possible.
I also found this though:
If the base creature didn’t have any natural weapons, it gains a slam attack that deals damage as if it were one size category larger than its actual size.
Given that exoskeletons can be applied to colossal creatures and it doesnt have extra rules, that's an example of another thing like INA that could indicate that you would continue increasing past colossal.
This exoskeleton text is similar to that found in Echohusk, Sunbaked Zombie, Waxwork and Zombie templates too. So its certainly not an isolated occurrence.
Conclusion: After finding those monster templates i've accepted that there is enough evidence to suggest effective size increases can surpass colossal size.
(And yes before its brought up i know multiple effective size increases from different sources wont stack)

AwesomenessDog |

Size Changes, Effective Size Changes, and Damage Dice Progression FAQ** spoiler omitted **...
beyond 2d6, Xd6 does not progress to d8, it stays d6 and same for d8 staying d8. But the equation is actually way simpler, the next step past 3d6/3d8 is double the previous number of die.
2d6, 3d6, 4d6, 6d6, 8d6, 12d6, 16d6, 24d6, 32d6, 48d6, 64d6... (and same for d8's) but I doubt you can get higher.

Azothath |
For the series posted, I believe you mean two steps back rather than one(previous) as you are not counting the current new index (which may confuse some people).
in the series 2,3,4,6,8,12,16,... if 2 is the first number(n{sub 1}), then 8 is the fifth number(n{sub 5}). Thus n{sub i+2}=2*n{sub i} where i>0.

AwesomenessDog |

For the series posted, I believe you mean two steps back rather than one(previous) as you are not counting the current new index (which may confuse some people).
in the series 2,3,4,6,8,12,16,... if 2 is the first number(n{sub 1}), then 8 is the fifth number(n{sub 5}). Thus n{sub i+2}=2*n{sub i} where i>0.
Yes, you double every two, but if you're looking to see what you go to next, ie "what is +1", you have to look to one behind you to get that difference of two and then double that.