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Awwww!
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Lets not go too far with the gratitude, though...
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And now, because I hadn't deleted Borderlands 3 after the free ride yet, instead of downloading 90-100 GBs, I only got an update of 43.8 GB.
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Wait a minute... Ultimate edition? Does that mean that all those locked exclamation marks advertising DLCs all over Sanctuary will be actual quests instead?!
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And updated.
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Whaaa?!
WHAT KIND OF MADNESS IS THAT?!?
AND I LOVE IT!
Ok, I just shot it for a few seconds so I might change my mind but the initial test firing against a few enemies was a blast.
Later it was noted that Mr. Torque actually managed to get rid of all the laser weapons across Pandora explaining why there were no laser weapons in B2.
And now his company has produced a laser weapon... Though of course, being Torque, it also supposedly fires rockets.
And yes, the usage of ALL CAPS is part of the joke, because that's how Mr. Torque speaks in-game.
*sort of, technically it happens after B2—one of the main characters of the series is interrogating one of the protagonists of Pre-Sequel who tells what actually happened between B1 and B2 describing the rise of B2 main boss to power, with half of the playable characters becoming bosses in B2.
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...(laser gun that fires rockets)...But do the rockets fire chainsaws?
No, that would be overkill.
Enemies are already melting in my glorious presence...
If they are in close and mid-range at least, that darned thing is very unruly on longer ranges... I might need keep something else for distance.
: is there a simple repeating pattern in which you arrive at the final value of X-sub-n for an arbitrarily decreasing amount Y-sub-n (described as a flat, consistent percentage z) such that when you reduce the new current value by z percentage of your current X-sub-n, you can do so n times quickly?
So, for example, let's start with 100 because it's a nice, round number (and also turns into % later). This would be either X-sub-1 or X-sub-0 (I forget proper notation because I don't uuuuuuuuuuuuse it until I do, which is right now, but still forgotten .)
Reduce the initial value X by 30% and this gets you to 70: simple so far. That's once!
Reduce that 70 by 30% and you get 49 (as shown by 30% of 70 is 21; 70-21=49). That's twice!
Reduce that 49 by 30% and you get 34.3 (as shown by 30% of 49 is 14.7; 49-14.7=34.3). That's thrice!
Now, obviously, we can do this ad infinitum, but what I'm really looking for is a formula to simplify doing that, so I don't have to keep multiplying z=30% by any give X-sub-n then subtracting that Y-sub-n from the X-sub-n and getting the X-sub-n.
It really feels like this should be a straight plug-and-chug "insert starting value for X, insert starting value for z, insert iteratives n, and enjoy life/winning" but I'm too ill-equipped at 5:10 AM to think.
(Also, while 100 is my starting value, I'm curious about the general formula; that shouldn't really affect anything, but I'm mentioning just in case I weirded it, somehow. My reason for starting with 100 is that it's easy to convert to %, as I'm secretly after a "final amount of <stuff> = ???% of original" after these reductions-by-percentage; but starting with 1 is almost as easy, and I'm much more curious about the formula at this point.)
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Nooooo!!!!
I knew it was gona to happen, but still...
NOOOO!!!
Nooooo!!!!
I knew it was gona to happen, but still...
NOOOO!!!
Me? You? Or loss of lasers?
(Or something else?)
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Awwww!
Wow. That gnome must have really done something awesome for you.
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: is there a simple repeating pattern in which you arrive at the final value of X-sub-n for an arbitrarily decreasing amount Y-sub-n (described as a flat, consistent percentage z) such that when you reduce the new current value by z percentage of your current X-sub-n, you can do so n times quickly?
So, for example, let's start with 100 because it's a nice, round number (and also turns into % later). This would be either X-sub-1 or X-sub-0 (I forget proper notation because I don't uuuuuuuuuuuuse it until I do, which is right now, but still forgotten .)
Reduce the initial value X by 30% and this gets you to 70: simple so far. That's once!
Reduce that 70 by 30% and you get 49 (as shown by 30% of 70 is 21; 70-21=49). That's twice!
Reduce that 49 by 30% and you get 34.3 (as shown by 30% of 49 is 14.7; 49-14.7=34.3). That's thrice!
Now, obviously, we can do this ad infinitum, but what I'm really looking for is a formula to simplify doing that, so I don't have to keep multiplying z=30% by any give X-sub-n then subtracting that Y-sub-n from the X-sub-n and getting the X-sub-n.
It really feels like this should be a straight plug-and-chug "insert starting value for X, insert starting value for z, insert iteratives n, and enjoy life/winning" but I'm too ill-equipped at 5:10 AM to think.
(Also, while 100 is my starting value, I'm curious about the general formula; that shouldn't really affect anything, but I'm mentioning just in case I weirded it, somehow. My reason for starting with 100 is that it's easy to convert to %, as I'm secretly after a "final amount of <stuff> = ???% of original" after these...
X_n = (1-z)^n X_0
So, in your examples, X_0 = 100, z = 30% = 0.3, so
X_1 = (0.7)^1(100) = 70%
X_2 = (0.7)^2(100) = 49%
X_3 = (0.7)^3(100) = 34.3%
etc.
X_n = (0.7)^n(100)
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Yay! My favorite game restaurant placemat activity as a kid! Connect the dots!! Except with a measuring tape, permanent markers and saws!
It's going to be awesome!!!
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How do you intend to get the Dorothys to stay still while you do so, and what are the saws for?
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What it's like living in California:
Weather Forecast: Nearly 3" of rain in the next 7 days
Native Californian:
Ah, yes, California! Land of 40" of predicted rain (and 15" of real rain) a year!
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I haven't understood what Tacticslion wrote, I understand what NobodysHome wrote even less...
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How do you intend to get the Dorothys to stay still while you do so, and what are the saws for?
Precision!
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Yes, the coloration of the Eldritch Foundry minis is VERY disappointing. One, the details were observable enough that with painting, it looks pretty good. The second one I did the details are so hard to see that painting has been quite difficult. It does not help that these are both short characters (a halfling and a very short human).
Hero Forge does have a colorized option - that is, they use colored resin to give you a colored mini. The reviews are mixed and the price point is...steep. I have not tried this option, but after my two EF minis, I will not likely go back.
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Speaking of greed...
I'm in my second annual all-division conference (1800+ participants). For the second time, they designed a "meet-n-greet" game where you're supposed to connect with people you don't know on Slack. For the second time, they offered prizes. For the second time, people are flagrantly cheating, even going so far as to write scripts that run 24 hours a day to up their scores. (A "normal" score for a social person would be around 3000-4000 points. There are people with 40,000+ points.)
At least this year the SVP called them out and said, "PLEASE stop cheating!"
But as long as:
(1) Prizes are involved, and
(2) There are no penalties for cheating,
it's going to continue to be stupid.
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...: is there a simple repeating pattern in which you arrive at the final value of X-sub-n for an arbitrarily decreasing amount Y-sub-n (described as a flat, consistent percentage z) such that when you reduce the new current value by z percentage of your current X-sub-n, you can do so n times quickly?
So, for example, let's start with 100 because it's a nice, round number (and also turns into % later). This would be either X-sub-1 or X-sub-0 (I forget proper notation because I don't uuuuuuuuuuuuse it until I do, which is right now, but still forgotten .)
Reduce the initial value X by 30% and this gets you to 70: simple so far. That's once!
Reduce that 70 by 30% and you get 49 (as shown by 30% of 70 is 21; 70-21=49). That's twice!
Reduce that 49 by 30% and you get 34.3 (as shown by 30% of 49 is 14.7; 49-14.7=34.3). That's thrice!
Now, obviously, we can do this ad infinitum, but what I'm really looking for is a formula to simplify doing that, so I don't have to keep multiplying z=30% by any give X-sub-n then subtracting that Y-sub-n from the X-sub-n and getting the X-sub-n.
It really feels like this should be a straight plug-and-chug "insert starting value for X, insert starting value for z, insert iteratives n, and enjoy life/winning" but I'm too ill-equipped at 5:10 AM to think.
(Also, while 100 is my starting value, I'm curious about the general formula; that shouldn't really affect anything, but I'm mentioning just in case I weirded it, somehow. My reason for starting with 100 is that it's easy to convert to %, as I'm secretly after a "final amount of <stuff> =
Great, they're speaking in tongues again! Time to hook up the fire hose! C'mon, Bessy! You know the drill!!
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Speaking of greed...
I'm in my second annual all-division conference (1800+ participants). For the second time, they designed a "meet-n-greet" game where you're supposed to connect with people you don't know on Slack. For the second time, they offered prizes. For the second time, people are flagrantly cheating, even going so far as to write scripts that run 24 hours a day to up their scores. (A "normal" score for a social person would be around 3000-4000 points. There are people with 40,000+ points.)
At least this year the SVP called them out and said, "PLEASE stop cheating!"
But as long as:
(1) Prizes are involved, and
(2) There are no penalties for cheating,it's going to continue to be stupid.
The prize could be an awkward dinner with a CEO asking for advice how to be so popular on social media.
Not that I am saying that you should give your bosses such an idea...
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Actually, when I looked at NobodysHome math second time I did understood the general idea of what is it about.
| 1 person marked this as a favorite. |
...: is there a simple repeating pattern in which you arrive at the final value of X-sub-n for an arbitrarily decreasing amount Y-sub-n (described as a flat, consistent percentage z) such that when you reduce the new current value by z percentage of your current X-sub-n, you can do so n times quickly?
So, for example, let's start with 100 because it's a nice, round number (and also turns into % later). This would be either X-sub-1 or X-sub-0 (I forget proper notation because I don't uuuuuuuuuuuuse it until I do, which is right now, but still forgotten .)
Reduce the initial value X by 30% and this gets you to 70: simple so far. That's once!
Reduce that 70 by 30% and you get 49 (as shown by 30% of 70 is 21; 70-21=49). That's twice!
Reduce that 49 by 30% and you get 34.3 (as shown by 30% of 49 is 14.7; 49-14.7=34.3). That's thrice!
Now, obviously, we can do this ad infinitum, but what I'm really looking for is a formula to simplify doing that, so I don't have to keep multiplying z=30% by any give X-sub-n then subtracting that Y-sub-n from the X-sub-n and getting the X-sub-n.
It really feels like this should be a straight plug-and-chug "insert starting value for X, insert starting value for z, insert iteratives n, and enjoy life/winning" but I'm too ill-equipped at 5:10 AM to think.
(Also, while 100 is my starting value, I'm curious about the general formula; that shouldn't really affect anything, but I'm mentioning just in case I weirded it, somehow. My reason for starting with 100 is that it's easy to convert to %, as I'm secretly after a "final amount of <stuff> =
of course
I knew it had to be something super-obvious, but I just was not seeing it. Uuuuuuuuuuuuuuuuuuuugh, I feel so dumb, now. Thank you!
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Great, they're speaking in tongues again! Time to hook up the fire hose! C'mon, Bessy! You know the drill!!: is there a simple repeating pattern in which you arrive at the final value of X-sub-n for an arbitrarily decreasing amount Y-sub-n (described as a flat, consistent percentage z) such that when you reduce the new current value by z percentage of your current X-sub-n, you can do so n times quickly?
So, for example, let's start with 100 because it's a nice, round number (and also turns into % later). This would be either X-sub-1 or X-sub-0 (I forget proper notation because I don't uuuuuuuuuuuuse it until I do, which is right now, but still forgotten .)
Reduce the initial value X by 30% and this gets you to 70: simple so far. That's once!
Reduce that 70 by 30% and you get 49 (as shown by 30% of 70 is 21; 70-21=49). That's twice!
Reduce that 49 by 30% and you get 34.3 (as shown by 30% of 49 is 14.7; 49-14.7=34.3). That's thrice!
Now, obviously, we can do this ad infinitum, but what I'm really looking for is a formula to simplify doing that, so I don't have to keep multiplying z=30% by any give X-sub-n then subtracting that Y-sub-n from the X-sub-n and getting the X-sub-n.
It really feels like this should be a straight plug-and-chug "insert starting value for X, insert starting value for z, insert iteratives n, and enjoy life/winning" but I'm too ill-equipped at 5:10 AM to think.
(Also, while 100 is my starting value, I'm curious about the general formula; that shouldn't really affect anything, but I'm mentioning just in case I weirded it, somehow. My reason for starting with 100 is that it's easy to convert to %, as I'm secretly
Why do we use these at the same time again?
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Actually, when I looked at NobodysHome math second time I did understood the general idea of what is it about.
Yeah.
Instead of -30% each time, it's multiply by
(70% raised to the [number of times you want to do this])
This is an incredibly obvious solution that I just feel incredibly annoyed at myself for failing to realize, not only because I've used it plenty of times on my own in the past for this exact reason, but especially as I was trying to do something very similar to that with the 30% part (and focusing on it) instead of the actual number I cared about, the 70% part. Yaaaay for approaching problems backwards!
bluuuurrrrrrrrrg
Third brownout in the last week.
>:(
BLARG
Now everything suuuuuuuuuuucks.
Internet connection is bad, Discord doesn't seem to work almost at all, and bluuuurrrrrrggggg.
Hello, John!
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I had a heroforge color mini made, as I got it cheap because of the kickstarter. Its OK. Some details do get lost, but you can see the ring on the finger of the character. The armor looks the best of all the colors.
Could I paint it better? Absolutely. Do I have time? ehhhhhhhhhhhhhhhhh no. So its a decent compromise.
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Some scams never get old -- at least they always make me giggle.
To NobodysHome's Father: Please renew your subscription as quickly as possible.
Which is an odd thing to ask for, since he hasn't been "subscribed" in 14 years.
The worst part?
This is from Consumer Reports, a nonprofit organization supposedly dedicated to protecting consumers, not bilking them.
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Nothing is quite as fun as going through thr plethora of mods you have for a game that make it playable to find the one that is causing the game to crash.
Yes, I would love a "First time?" meme from GothBard.
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Nighty
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Vest!
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Precision!
Looks fantastic, my dude!
Welp! Fun, fun, fun, my tire enTIREly blew out today!
You can see through it to the road on the other side!
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Sorry to hear that. Damned caltrops!!
Sorry to hear that. Damned caltrops!!
Almost looks like it!
Just for those who may worry, I’m already at a place—safely. It physically hurts spending that much money, but apparently 3/4 of my tires were garbage, this one was just the first to go, so.
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Sorry to hear that. Damned caltrops!!Almost looks like it!
Just for those who may worry, I’m already at a place—safely. It physically hurts spending that much money, but apparently 3/4 of my tires were garbage, this one was just the first to go, so.
Almost the exact same thing when I was teaching Impus Major to drive. He hit a curb and the tire pretty much exploded. Went to the tire shop and the moment the guy looked at the tires he shook his head and said, "Nope. You're going to need all four."
And good tires are expensive.
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NobodysHome's Gripes of the Day:
(1) Yet another 6:30 am car alarm in the neighborhood. Years ago, multiple consumer advocacy groups conclusively proved that car alarms do nothing to protect your car; they are entirely for show and to irritate your neighbors. Yet you can't buy a car without one. (The Celica has a disabled car alarm system we refused to pay for. The Prius came with a built-in one which has "only" gone off 3-4 times in the car's 15-year lifespan.)
I'd love to see the entire U.S. consumer population start refusing to pay for them. "I see the MSRP on this car is $22,000, with $800 for a car alarm system. Well, right off the bat I'm taking $800 off the price of the car because I'm not paying for that."
Just a massive, concerted effort to get those things the h*** out of our cars.
(2) As I've mentioned, I'm in our annual professional 3-day conference, where we're expected to spend all day, every day attending the conference. Some of my co-workers are choosing to work during the breaks instead of participating in the social games they're supposed to. No issues there. EXCEPT they're harassing me and asking ME to do a bunch of work during the breaks to help them out.
Nope. I have been assigned to attend this conference by my Senior Vice President, and he has made it abundantly clear that he does NOT want me working during the conference. So if you choose to work overtime that's your business. I'm not helping you, and don't bug me.
Sorry to hear that. Damned caltrops!!Almost looks like it!
Just for those who may worry, I’m already at a place—safely. It physically hurts spending that much money, but apparently 3/4 of my tires were garbage, this one was just the first to go, so.
Almost the exact same thing when I was teaching Impus Major to drive. He hit a curb and the tire pretty much exploded. Went to the tire shop and the moment the guy looked at the tires he shook his head and said, "Nope. You're going to need all four."
And good tires are expensive.
They are.
In my case it was, “Huh, it’s a bit cool today.” Drop kids at school with no incident. “Huh, says low tire pressure.” Nothing visible, get gas. “Huh, the car is handling a bit funny.” Head toward place to put air in tire. “Huh, the car is handling really badly.” That place is no longer useful because it somehow entirely separated on the way there.
(I’ve totally hit curbs with tires before; that just wasn’t in this particular case, the exact cause of which remains a mystery!)
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NobodysHome's Gripes of the Day:
(1) Yet another 6:30 am car alarm in the neighborhood. Years ago, multiple consumer advocacy groups conclusively proved that car alarms do nothing to protect your car; they are entirely for show and to irritate your neighbors. Yet you can't buy a car without one. (The Celica has a disabled car alarm system we refused to pay for. The Prius came with a built-in one which has "only" gone off 3-4 times in the car's 15-year lifespan.)
I'd love to see the entire U.S. consumer population start refusing to pay for them. "I see the MSRP on this car is $22,000, with $800 for a car alarm system. Well, right off the bat I'm taking $800 off the price of the car because I'm not paying for that."
Just a massive, concerted effort to get those things the h*** out of our cars.
You barely find them in cars over here anymore. Its really strange nowadays when you DO hear one of them go off.
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...car alarms...You barely find them in cars over here anymore. Its really strange nowadays when you DO hear one of them go off.
Admittedly, I haven't shopped for a new car in 15 years, but my impression is that you can't purchase a car in the U.S. without an alarm.
Any other U.S.ers want to confirm/deny that?