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huzzah!
I win AND a show!

Dark Archive

*eats everyone*

I win!


cuts himself out of the gut with a swiss army knife

WINNING!!!


3D20= 18+12+20=50
golf sucks, I play full contact sports.....lol

The Viking kills anyone standing, I win!!!!!!!!!!


::First shot on hole 3:
3d6 ⇒ (2, 6, 2) = 10
It's in the hole!

Score so far:

Hole 1: -2 (eagle)
Hole 2: +0
Hol3 3: -3 (hole in one)

.


look another kill for the Viking!!!!!!!!!!!!!!


::First shot on hole 4
3d6 ⇒ (6, 1, 1) = 8
It's in the hole!

Score so far:

Hole 1: -2 (eagle)
Hole 2: +0
Hole 3: -3 (hole in one)
Hole 4: -3
.


I don't get all this golf stuff, who needs all these silly games, I have already WON this blog!


DJ-Bogie wrote:
I don't get all this golf stuff, who needs all these silly games, I have already WON this blog!

>here are the rules<


Hey, look at that. I finished the golf course with a score of -123.9.

Scarab Sages

Pathfinder Battles Case Subscriber; Pathfinder Maps, Pathfinder Accessories Subscriber; Pathfinder Roleplaying Game Superscriber

Fourth Hole:

3d6 ⇒ (6, 5, 6) = 17

Scarab Sages

Pathfinder Battles Case Subscriber; Pathfinder Maps, Pathfinder Accessories Subscriber; Pathfinder Roleplaying Game Superscriber

This is spooky. I wish I could be this good when I am playing.

Fourth Hole -3.

Total -12.


The Nasty Orc wrote:
Nasty Orc takes the clubs beats KaeYoss and Charles Scholz over the head with it. ...Nope Orc win silly clown men.

KaeYoss takes club and shoves it up nasty orc.

I win.

Scarab Sages

Pathfinder Battles Case Subscriber; Pathfinder Maps, Pathfinder Accessories Subscriber; Pathfinder Roleplaying Game Superscriber

Fifth Hole
3d6 ⇒ (3, 1, 5) = 9

Scarab Sages

Pathfinder Battles Case Subscriber; Pathfinder Maps, Pathfinder Accessories Subscriber; Pathfinder Roleplaying Game Superscriber

Just shy.
Second shot.
3d6 ⇒ (2, 5, 5) = 12

Scarab Sages

Pathfinder Battles Case Subscriber; Pathfinder Maps, Pathfinder Accessories Subscriber; Pathfinder Roleplaying Game Superscriber

Nice putt.

Fifth Hole -2

Total -14


What what? In the putt putt!

Dark Archive

Go ahead and play your game but I am going to win the important game (this one).


::First shot on hole 5:
3d6 ⇒ (3, 3, 2) = 8
It's in the hole!

Score so far:

Hole 1: -2 (eagle)
Hole 2: +0
Hole 3: -3 (hole in one)
Hole 4: -3
Hole 5: -3

.


ティファ・ロックハート


Like I said, I don't need golf when I have already WON this game


it is prolly best to not install your 3rd eye in the front...


DJ-Bogie wrote:
Like I said, I don't need golf when I have already WON this game

The game. You just lost it!


KaeYoss wrote:
DJ-Bogie wrote:
Like I said, I don't need golf when I have already WON this game
The game. You just lost it!

Crap!

Wait a sec...OK winning again!


DJ-Bogie wrote:
KaeYoss wrote:
DJ-Bogie wrote:
Like I said, I don't need golf when I have already WON this game
The game. You just lost it!

Crap!

Wait a sec...OK winning again!

Once you have lost the Game, you have lost forever. You cannot "unlose". Mainly because that's not a word.

Dark Archive

So you have lost Kae Yoss thanks for playing you can't unlose so ..... I am winning now.


Gruumash . wrote:
So you have lost Kae Yoss thanks for playing you can't unlose so ..... I am winning now.

Nah, I can do anything. Including winning.


Hole -1:
3d6 ⇒ (2, 3, 2) = 7


Hole -2:
3d6 ⇒ (6, 1, 4) = 11


Hole -3:
3d6 ⇒ (4, 4, 4) = 12


Hole -4:
3d6 ⇒ (6, 4, 6) = 16


rolling up a FIGHTER:

3d6 + 1 ⇒ (2, 2, 2) + 1 = 7
3d6 + 1 ⇒ (4, 5, 4) + 1 = 14
3d6 + 1 ⇒ (3, 5, 3) + 1 = 12
3d6 + 1 ⇒ (6, 1, 3) + 1 = 11
3d6 + 1 ⇒ (1, 2, 2) + 1 = 6
3d6 + 1 ⇒ (1, 6, 1) + 1 = 9


Rolling up a MAGIC-USER:

3d6 + 1 ⇒ (5, 3, 4) + 1 = 13
3d6 + 1 ⇒ (6, 5, 4) + 1 = 16
3d6 + 1 ⇒ (2, 1, 6) + 1 = 10
3d6 + 1 ⇒ (3, 3, 6) + 1 = 13
3d6 + 1 ⇒ (6, 1, 3) + 1 = 11
3d6 + 1 ⇒ (2, 2, 4) + 1 = 9


Rolling up a THIEF:

3d6 + 1 ⇒ (4, 4, 6) + 1 = 15
3d6 + 1 ⇒ (6, 1, 4) + 1 = 12
3d6 + 1 ⇒ (2, 3, 2) + 1 = 8
3d6 + 1 ⇒ (4, 1, 3) + 1 = 9
3d6 + 1 ⇒ (3, 2, 4) + 1 = 10
3d6 + 1 ⇒ (4, 3, 4) + 1 = 12


Rolling up a MONK:

3d6 + 1 ⇒ (4, 3, 2) + 1 = 10
3d6 + 1 ⇒ (5, 2, 4) + 1 = 12
3d6 + 1 ⇒ (1, 2, 3) + 1 = 7
3d6 + 1 ⇒ (6, 1, 6) + 1 = 14
3d6 + 1 ⇒ (2, 4, 4) + 1 = 11
3d6 + 1 ⇒ (3, 5, 6) + 1 = 15


Rolling up CTHULHU:

3d6 + 1 ⇒ (1, 5, 6) + 1 = 13
3d6 + 1 ⇒ (4, 5, 6) + 1 = 16
3d6 + 1 ⇒ (1, 1, 6) + 1 = 9
3d6 + 1 ⇒ (2, 4, 4) + 1 = 11
3d6 + 1 ⇒ (1, 4, 2) + 1 = 8
3d6 + 1 ⇒ (1, 3, 1) + 1 = 6


ON


YOUR


MARK


FIRE ALL TUBES.


It is a nice day.


1 person marked this as a favorite.

Bayesian Tracking
―――――――――――

You have designed a MARS ROVER. (good job)

It has a sensor that can detect the density of some rock.

Unfortunately the sensor is noisy. The number returned by the sensor is: x = 3∙d + N(3, 100), where
d is the actual density, and N(μ, σ²) specifies a Gaussian distribution with mean μ and variance σ².
You decide to use a Bayes’ filter to help overcome the noise of the sensor and to help you
detect which type of rock you are sensing.

Here are rough numerical approximations to the sensor model in tabular form.

......................................Sensor Output............................................
...........|..x < 2..|..2 < x < 8..|..8 < x < 14..|..14 < x < 20..|..x > 20
D....0..|...0.46...|......0.23......|.......0.18.........|........0.09..... ..|......0.04
E
N....2..|...0.24...|......0.22......|.......0.23.........|........0.17..... ..|......0.14
S
I....4..|....0.10...|......0.15......|.......0.22.........|........0.23.... ...|......0.30
T
Y....6..|...0.03...|......0.07......|.......0.15.........|........0.22..... ..|......0.53

(a) Derive Bayes’ rule for two probabilities (starting with a Venn diagram).
P(A|B) =?

(b) Which type of Bayes’ filter is most appropriate for this problem: a Kalman
filter, a particle filter or a table based Bayes’ filter. Why?

  • For the rest of this question we will assume a table based filter (because it is easiest to ask
    questions about, don’t assume it is the best for the question above simply because the following
    questions use it):

    (c) What is your state representation for your table based filter?

    (d) What is your initial state assuming you have no idea what sort of rock you
    are currently sensing?

  • Your sensor returns output of 3 when sensing a rock for the first time.

    (e) What is the your new state?

    (f) At this point, what is your best estimate as to what density of rock you are
    sensing?

  • You sense the same rock again, and this time get receive output of −1.

    (g) What is your new state?

    (h) At this point, what is your best estimate as to what density of rock you are sensing?

    Spoiler:

    [ you have 10 minutes for this problem ]


  • If you haven't been paying attention, the answer here is always 42!

    And, "I Win"


    Tensor wrote:


    It is a nice day.

    How would I know? The day's outside. I don't go there. That's where they get you with the mind control rays you know.


    This was a triumph


    KaeYoss wrote:
    This was a triumph

    And now the Triumph is mine. Although I don't ride motorcycles, so I guess I'll just sell it.

    Dark Archive

    gran rey de los mono wrote:
    KaeYoss wrote:
    This was a triumph
    And now the Triumph is mine. Although I don't ride motorcycles, so I guess I'll just sell it.

    *steals the Triumph and the win*

    Yay I win and got a motorcycle too.


    We have a winner!


    Billy Mays_ wrote:

    *steals the Triumph and the win*

    Yay I win and got a motorcycle too.

    Oy! Give back the motorcycle! I need the money. Of course, if you are interested I can make you a good deal.

    I don't need you to return the win, as I am capable of stealing it back myself.

    Liberty's Edge

    42

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