Experience Point progression Formulas?


Alpha Release 3 General Discussion


I was checking out the Xp progression (Slow,Medium and Fast) and I can't see on which formula these progressions are based upon!

I am trying to figure out a mathematical formula for each progression that I could use in Excel... Any ideas?

Thanks!

RiTz21

Liberty's Edge

Pathfinder Roleplaying Game Charter Superscriber; Pathfinder Starfinder Adventure Path, Starfinder Roleplaying Game, Starfinder Society Subscriber

I asked this awhile back, there isn't one exactly.

I don't remember what the number was, but the XP chart is actually based on having a fix number of encounters each level.

Paizo Employee Director of Game Design

The reason why you are having some troubles nailing it down is because there is a small amount of rounding involved.

The system starts out by assuming 13.3, 20, and 30 encounters per level in a group of four characters. The XP per encounter formula follows a base 400, increased by 50% for the next level (600), and increased by 100% (from the first level base) for the level after that (800). From that point forward, the XP system follows this progression, with each level worth double the amount of the level two levels lower. This XP system allows the encounter building system and the XP system to sync up.

Complicated, but it works.

Jason Bulmahn
Lead Designer
Paizo Publishing

Liberty's Edge

Pathfinder Roleplaying Game Charter Superscriber; Pathfinder Starfinder Adventure Path, Starfinder Roleplaying Game, Starfinder Society Subscriber

I think I'll copy and paste that into notepad for future reference. :)


*puts formula into spreadsheet*

Yay!


RiTz21 -- I had a couple of possible formulas that I worked out in another thread, but I can't find the $#%! post any more...

Jason is correct, though; there is rounding, and then rounding of the rounded values, etc. so that an exact formula is probably impossible to get.


I found my notes. The formula for the Medium XP column would be:

F(i) = 2000 * (2^floor(i/2) - 1) + 3000 * (2^floor((i-1)/2) - 1)

...rounded to "2.5" significant figures.

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