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Rules are pretty simple. Solve the riddle then post your own. If you don't want to post your own or don't have a riddle, just choose to pass and whoever else can post one.
Google eats kittens so don't use it to cheat and look for answers. When the world hangs in the balance and the sphinx is asking you a riddle and you can't access you're google-fu, the world will be mad at you for not sharpening your mind.
(Starting. I'll even Pathfinder it up for the forums)
Three couples reserved rooms at this nice inn at Riddleport which only has three rooms total. The couples are Merisiel and Seltyiel (girl/guy), Valeros and Alahazra (guy/guy), and Seoni and Kyra (girl/girl) (I'm not trying to insinuate anything with the pairings. They could just be rooming up or whatever. Not important). The three pairings leave their luggage downstairs to be carried up to their rooms. However, due to a mix up, none of the pairings received the rooms they had initialy reserved so the list the bellhop has is no longer accurate.
The problem is, the mute bellhop picked the pockets of all the visitors as a true Riddleport citizen would do and doesn't want to risk a face to face meeting in case they might realize somehow that he stole from them (he might have been a thief but he had a horrible poker face). He just wants to leave their bags outside their doors.
So the bellhop gets an idea of using the magical phone systems they have to call the rooms to find out which couple is in which room now. Since he can't talk, he has to listen to the voice to try and figure out which couple is in which room by hearing the voice of whoever answers the phone. The bellhop hasn't heard them speak before so matching a male or female voice to a specific person is off the table. All he can tell is whether the person who answers is male or female.
The riddle is how many times did the bellhop have to call the rooms before he can figure out which couple is in which room so he can leave their bags outside their door.
Give both the answer and WHY it's the answer. Just guessing random numbers won't cut it.