
Dalvyn |
Pathfinder Adventure Path Subscriber

Charles Evans 25 wrote:
Galdor the Great wrote:Simple question...what are the odds of rolling 86 on 10d10?Well there are approximately 10000000000 different permutations (I think that is the word) for a roll of 10d10; all you need to know are the number of those which total 86.
I found 810040 possibilities, so the probability is
810 040 / 10 000 000 000,
that is, 0.008%.
The most probable result is 55, with about 4%.

Tensor |

I tallied all the possible ways you can roll a total of 86 on 10d10, and came up with: 810,040.
So, Pr[sum of 10d10 is 86] = 810,040 / 10,000,000,000
p.s. because 10d10 is a 10 dimensional cube I actually had to look up the counting method in an old manuscript dedicated to Yog-Sothoth titled high-dimensional membranes & manifolds.
Edit: I just noticed Dalvyn beat me to the punch.

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RickSummon wrote:
If you look up "Dice" on Wikipedia, there's a formula near the bottom of the page that lets you calculate the probability of rolling a total of k on i dice with s sides each. If you have a programmable calculator, it's easy to write a function to calculate it.
But for a perpetually random result, a dice would never be rolled...that you have spells certain doom for us all.