We ran into that one yesterday. And we really love (being non-native English speakers) when we are puzzled on whether we just can't read plain Elvish or whether indeed there may be a wording issue worthy of a new thread. So in doubt, there it is:
This is an English puzzle for Mike, the master of maths-and-English riddles.
I'm playing Drelm (Melee d10+2) using his Whip (Melee+d6) and a Caravan Guard (+d4) for a combat check. But he has the Curse of Withering (During your check, when you assemble your dice, replace all of your highest-size dice with the same number of the next lower-size dice).
Does he roll d8+d6+d4+2 or 2d6+d4+2?
I. e. does "next lower-size" refer to dice existing in the box or to dice assembled for the check?
Note that
- in the first case Curse of Withering is ineffective if I only roll d4s
- in the second case, Curse of Withering is ineffective if all the dice I assembled are of the same type
That was our Sphinx riddle of the week...
d8+d6+d4+2
You use the next lowest size that exists in the game.
It doesn't make sense to use the next lowest die you are already using. Say you are rolling 3d10. The Curse of Withering then has no effect whatsoever? No.
Dice in the box. Your d10s become d8s, regardless of whether you were previously rolling d8s.
I'm surprised no one's yet asked whether they can bring in d5s, d7s, or d11s.
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Dice in the box. Your d10s become d8s, regardless of whether you were previously rolling d8s.
I'm surprised no one's yet asked whether they can bring in d5s, d7s, or d11s.
Can I use d5's and d3's? You say "dice in the box", but a d10 can easily be used as a d5, and a d6 can easily be used as a d3, so I can do both of those with just dice in the box. :)
(I actually have some physical d3's too, they've already proven useful in PACG for determining random locations when there are 3 choices, or determining random players since my playgroup is 3 people).