diagonally


Beginner Box


sorry if there is a thread allready but my seachbox buged so i am not sure if theres is any...

so SPEED 30 FEET (6 SQUARES) Fighter Human
in the page 55 in the Hero Handbook

Valeros's 1st move costs 5 feet +

his 2nd move costs 5 feet = 10feet (2Squares) +

and his
3rd move is his second diagonal
so it costs 10 feet. = 20feet (3Squares 1 up, 2 diagonal) +

Next he moves
into difficult terrain, which costs
him 10 feet. = 30 feet (4Squares 1up,2diagonal + difficult terrain)

so he cant move anymore ? but in the Hero Handbook he still moves 15 feet so 45feet ? or have i understand this movement actions wrong?

or is it up,2diagonal is = 10feet ? because 2 diagonals is counted for 5feet ? so 1up(5feet) + 2 diagonal(5feet) =10feet

then difficult terrain 10+10+ (diagonaly into diffterrain is 10 not 15?)
10 = 30 feet ?

to but this simply 2 diagonal is 5 feet not 10feet ? example 1up,1diag,1up,1diag is 15feet ?


Pathfinder Lost Omens, Rulebook Subscriber

I don't have the beginners box, so can't totally tell you what's up with the example you're giving, but here's what I can tell you about diagonal movement and hindering.

A diagonal is actually ~7.5ft via the pythagorean theorem (actually a little less), but to keep it simple Pathfinder does first diagonal costs you 5ft and the second cost you 10ft cause 7.5ft twice is 15ft which is the same as 5 plus 10. This keeps you from having odd remainders of movement left like 3ft.

Now if you combine with hindering terrain where all movement costs are doubled it makes sense just to use 15ft for a diagonal (7.5*2) instead of doing some sort of 10ft first, 20ft second deal, since 15 is divisible by 5 and will leave you with an amount left you can move that can be used up perfectly in 5ft steps.


Every other diagonal movement during a round counts as an extra 5 feet. There are GMs who throw this rule out since it adds confusion.

So up, diagonal, up, diagonal = 5+5+5+10 = 25 feet. Difficult terrain makes whatever normal movement costs double.


Thanx for your answers B). Now i and my friends understand this little better. now it is 6 squares (30feet) up-down-left-right and diagonally 5+10+5+10 4squares ? (this are all diagonally)

Here are few pictures that i draw about movement

http://imgur.com/NeDP5Ym up-down-left-right = 5+5+5+5+5+5= 30feet one direction

http://imgur.com/Uv53Q6Y up, diagonal, up, diagonal = 5+5+5+10 = 25 feet.

http://imgur.com/efmG6Ix up, diagonal, up, diagonal + up = 5+5+5+10+5 = 30 feet.

is this calcu right http://imgur.com/a6MPiQA up,diagonal,up,diagonal,diagonal = 5+5+5+10+5 = 30feet

and if all the movement is diagonally http://i.imgur.com/vQjt1aB.jpg 4squares is 30feet 5+10+5+10 = 30feet


These all look correct. Good job, soppathekeitto.

To Gullyble Dwarf: it's actually closer to 7 than 7.5.
It's the square root of 2, times 5, which my calculator gives as
7.0710678 plus change. But thinking of it as one and a half square is a good shorthand.


ok thanx this simplies thing for me every second diagonally is counted for 5+5 aka doublecount


Gullyble Dwarf explained well how movement works in Pathfinder.

I'm using some house rule for movement...
It's rather simple : double characters (and NPC & monsters) movement allowance and double the movement costs.

That gives :
- 12 movement points for a Human (base 30 ft or 6 squares)
- 8 movement points for a Halfling (base 20 ft or 4 squares)
- moving across clear terrain following the squares : 2 MP/square
- moving across cear terrain diagonally : 3 MP/ square
- moving across difficult terrain straight : 4 MP/square (2 x 2 MP)
- moving across difficult terrain diagonally : 6 MP/square (2 x 3 MP)

This way, an Elf (30 ft base movement, 12 MP) can go up to 6 squares straight on clear terrain (6 x 2 MP = 12 MP) or 2 squares diagonally on difficult terrain (2 x 6 MP) or any combination of straight/diagonal and clear/difficult.

I believe it makes all simpler than alterning "5 ft" and "10 ft" base costs.

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