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Let's say I have an unchained rogue (knife master) 5 and Investigator (Questioner)5 and Arcane Trickster 3. If I take accomplished sneak attacker, does it increase the sneak attack of both the rogue class and the arcane trickster class, or just one of the classes?
Without the accomplished sneak attacker, this character would have 4d6 sneak (3d6 from U-Rog and 1d6 from AT).
I know Hero lab doesn't always get the rules right, and it seems to think that when I took ASA, that both classes sneak attack went up by 1 die. If it's correct, I'd still be under half my total level for sneak attack dice at 6d6. If it only applies to one class, then the correct total would be 5d6.
For reference from AT:
Sneak Attack
This is exactly like the rogue ability of the same name. The extra damage dealt increases by +1d6 every other level (2nd, 4th, 6th, 8th, and 10th). If an arcane trickster gets a sneak attack bonus from another source, the bonuses on damage stack.
Each class granting the character sneak attack tracks their +d6's separately even though the two sources explicitly stack.
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Herolab definitely messed this one up. The feat benefit says that your sneak attack damage increases by 1d6, so that should be a single increase overall.
You only get one sneak attack damage progression. Arcane trickster even tells you that if you have another source of sneak attack you stack them together to determine your overall sneak attack damage.
So you would increase you sneak attack damage by 1d6, total.
Accomplished Sneak Attacker gives you +1d6 total, it doesn't matter how many classes you are getting Sneak Attack from.
For example, if you were hypothetically a 3Rogue/4Slayer/4Spy/5ArcaneTrickster, you wouldn't get +4d6 Sneak Attack from Accomplished Sneak Attacker-- you'd just get +1d6 to your total SnA dmg and that's it.