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As has been said, Seasons 0, 1, 2, and 3 assume 4 players. When calculating APL for these tables. Add up all character levels, divide by the number of characters and then add +1 for every character past 4 (so +1 for 5, +2 for 6) to the overall APL. This will alot of times push a table of 6 into the high tier.
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As has been said, Seasons 0, 1, 2, and 3 assume 4 players. When calculating APL for these tables. Add up all character levels, divide by the number of characters and then add +1 for every character past 4 (so +1 for 5, +2 for 6) to the overall APL. This will alot of times push a table of 6 into the high tier.
This is the first time I've ever seen this rule. The Guide to Organized Play states:
Determining Subtiers
In order to determine which subtier a mixed-level group
of PCs must play in, calculate the group’s average party
level (APL). Divide the total number of character levels by
the number of characters in the party. You should always
round to the nearest whole number. If you are exactly at
0.5, let the group decide which subtier they wish to play.
(...)
For scenarios written in Seasons 0 to 3, when the APL is
in between subtiers, a party of six or seven characters must
play the higher subtier. Parties with four or five characters
must play the lower subtier. In the fringe case where there
are no players that are high enough to have reached the
subtier level (such as a party of six 3rd level characters),
the group may decide to play down to the lower subtier.
I assume a Venture Captain wouldn't just change the PFS rules, so it has to be stated somewhere - I just can't find it. Richard, could you please show me where it stands? Because then I've done it wrong in the past...
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As has been said, Seasons 0, 1, 2, and 3 assume 4 players. When calculating APL for these tables. Add up all character levels, divide by the number of characters and then add +1 for every character past 4 (so +1 for 5, +2 for 6) to the overall APL. This will alot of times push a table of 6 into the high tier.
That's an, uh, interesting take on a rule that was removed seasons ago.
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Assuming Richard's calcs; it ends up 6x1=6, /6=1, +2 on extra characters.
Ends up on 3, while the scenarios are 1-2 & 4-5 orientated. Animal companion excluded.
I've proposed to run the other of the two for the last two who wanted to play and fill the 2 slots through recruitment. Seems the easiest solution, safest too.
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Assuming Richard's calcs; it ends up 6x1=6, /6=1, +2 on extra characters.
Ends up on 3, while the scenarios are 1-2 & 4-5 orientated. Animal companion excluded.I've proposed to run the other of the two for the last two who wanted to play and fill the 2 slots through recruitment. Seems the easiest solution, safest too.
Richard's numbers are a misremembering of a rule that was removed in Season 5. They are not how it's done anymore.