Heathwool
|
I kind of want clarity on his power that states: "At the start of your turn, you may discard any number of cards from the top of your deck. Each other character may shuffle random cards from his discard pile into his deck; the total number of cards shuffled must not exceed (1 plus) twice the number of cards discarded"
If I invest the power feat, can I choose to discard 0 cards and heal everyone else 1 card?
Eliandra Giltessan
|
The answer is "no" according to Vic's post here. When you do something with "any number of cards," it has to be at least 1.
Also, the total number of cards shuffled must not exceed twice the number of cards discarded. So if you discard one card, two players may each heal one card, or one player may heal two cards.
| elcoderdude |
The answer is "no" according to Vic's post here. When you do something with "any number of cards," it has to be at least 1.
Also, the total number of cards shuffled must not exceed twice the number of cards discarded. That means that all the cards shuffled among characters added up cannot equal that. So if you discard one card, two players may each heal one card, or one player may heal two cards.
Your link didn't work for me for some reason. Trying again.
Also, I don't understand the line I bolded above. The total healed cannot exceed twice the number discarded. It can certainly equal it.
| Parody |
It doesn't work because of extra text before the intended URI. I bolded the part that should have been removed below (and made the rest a link):
http://paizo.com/threads/<br%20/>http://paizo.com/paizo/blog/v5748dyo5lil8?Magic-and-MysteryOracle-Class-Dec %20k-Preview#30
There's also a space in the URI that was encoded as %20; that space shouldn't be there, but this forum sticks them in sometimes when you paste the text of a link in a post. (Or maybe any long stretch of text without a break?)
Anyway, I'm not sure how you got what you did. FWIW, I get the link to a specific post by right-clicking (context-clicking) on the post date on the right and picking "Copy Link Address" (or equivalent).
Hope this helps.