So I see in the Sticky thread via JJ that the Nights of Dread bloom doesn't result in the PCs kingdom losing a hex. I'm totally cool with that. However nothing is mentioned anywhere about how much unrest is incurred from this bloom.
I was thinking of having the bloom cause 1 unrest for each day it remains active in the nations capital. After all, there is a 'serial killer' running rampant in the capital for days. Is this reasonable? How did everyone handle this specific bloom
Unrest becomes relevant once per month. The entirety of the bloom cycle only takes one month. And then you've either won the campaign, or your kingdom is bottled. So it's not really relevant.
Besides, stopping the action of bloom cycle to do a kingdom-building step (which should be pretty timeconsuming at this size) would result in bad pacing IMO, and as a GM I would try to make sure that didn't happen.
But in the event that your PCs defeat the bloom cycle, and then want to take a breather before assaulting The House, then I'd posit the compounded effects of the other events (like the attack of the High Folly, or the Jabberwocky) would have a much greater impact on unrest than "that nightmare thing that happened a few weeks ago." And the guidance for winning other major victories in the AP has been "reduce unrest to 0".
Hope that helps.
That's not entirely true. Unrest applies penalties to each of the kingdoms checks. Over the course of the blooms manifesting the kingdom is allowed (stability?) checks per day to learn of each as they spread.
I do agree with you that at this point in the campaign it really doesn't matter though. I am gonna settle on 1 unrest per night in which npcs were killed.
Thanks