Hoping to play this tonight at the store. Does defeating a "henchmen" in this scenario grant an opportunity to close the location? Normally defeating a villain closes the location automatically, but the scenario says to treat them like henchmen. The rules say that defeating henchmen normally gives you an opportunity to close a location and it will say so on the card. Technically the villain cards say Close the location so I am not sure what the answer is. My guess is they don't grant the opportunity, but wanted to make sure. Thanks, Wray
Quick question. The Scenario specific text says "When you advance the blessings deck, your ship is dealt structural damage equal to the number of unoccupied open locations." But the scenario also says the "The Party does not have a ship". So how do you handle the structural damage since all the locations are the ship (neat touch btw)? i.e. What happens if the "ship" is wrecked? How does the party repair the ship? Or once the ship is wrecked is remains that way? Thanks, Wray
Avatar of Dagon question. The check to defeat is: Combat 42 then Combat 42 or Divine 24. Does this mean:
My reading of the rules seems to indicate B which makes the big bad of the whole scenario not that tough. Of course you have to get to him, but one Divine 24 check is a lot easier to achieve without a Combat 42 preceding it.
Follow up questions since we are getting ready to play this tomorrow. 1) Since everyone is a villain, if you defeat them their location is automatically closed correct? 2) The phrase on the Adventure card "Kerdak Bonefist is undefeated" has me a bit confused. Does this mean after you encounter the Filthy Lucre he is just shuffled back into the location deck just like a normal bane you failed to defeat? 3) Since there is a Blessings deck I assume you can try again if you run out of time? Thanks, Wray
The text on the card says "If you defeat a henchmen put it in a henchmen pile next to this card. When you encounter Barnabas Harrigan, each other character must summon and encounter a random henchmen from the henchmen pile." If you are playing with four players and there is only one henchmen beside the card do the other three players each encounter the same henchmen or does only one other player encounter a henchmen? If only one other player is it random or do we get to decide who encounters the henchmen? Thanks, Wray |