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Starting Gold:

2d6 ⇒ (2, 2) = 4


For the record, I will be using Set 3 for all the beautiful even numbers and of course that sweet, sweet perfect 18.

My stats (currently unassigned) will be: 10, 12, 12, 14, 15, 18

I'll be playing Sorcerer.


Sup, b#&@#ez

Set 1:

2d6 + 6 ⇒ (3, 2) + 6 = 11
2d6 + 6 ⇒ (4, 3) + 6 = 13
2d6 + 6 ⇒ (5, 6) + 6 = 17
2d6 + 6 ⇒ (5, 1) + 6 = 12
2d6 + 6 ⇒ (5, 5) + 6 = 16
2d6 + 6 ⇒ (5, 1) + 6 = 12

Set 2:

2d6 + 6 ⇒ (6, 1) + 6 = 13
2d6 + 6 ⇒ (1, 4) + 6 = 11
2d6 + 6 ⇒ (6, 3) + 6 = 15
2d6 + 6 ⇒ (3, 4) + 6 = 13
2d6 + 6 ⇒ (1, 5) + 6 = 12
2d6 + 6 ⇒ (4, 6) + 6 = 16

Set 3:

2d6 + 6 ⇒ (5, 1) + 6 = 12
2d6 + 6 ⇒ (2, 6) + 6 = 14
2d6 + 6 ⇒ (6, 6) + 6 = 18
2d6 + 6 ⇒ (3, 6) + 6 = 15
2d6 + 6 ⇒ (2, 4) + 6 = 12
2d6 + 6 ⇒ (3, 1) + 6 = 10

So no crazy homebrewed classes or weird-ass obscura from rulebooks only two people have ever read?

How dull.