| Vidmaster7 |
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Tremendous Strength: For Strength scores not shown on Table: Carrying Capacity, find the Strength score between 20 and 29 that has the same number in the "ones" digit as the creature's Strength score does and multiply the numbers in that row by 4 for every 10 points the creature's Strength is above the score for that row.
Do you guys interpret this as (4x4x4) or (4+4+4) as an example say I have a 50 strength would I multiply the amount by 12 (4+4+4) or 64 (4x4x4)?
| Tacticslion |
Heh. I was about to comment. My reading is the same as Matthew's.
To be fair, Vid, we were discussing a hypothetical Strength score of ~2,929... XD
I'm going to snip a bit of our conversation from before, just to show a few points of conversation:
(Clipped to relevant parts for the over-all discussion, not specific examples.)
-=========Took the below out of quote box, as it looked bad and confusing=========-
But here was my logic (and I'm ready to be told, "Tac, you're being dumb." That happens.):
If I get 39 Str, that multiplies by x4.
If I then get 49 Str, that multiplies by x4.
If I then get 59 Str, that multiplies by x4.
To me, that pattern looks like I'm going to go x4x4x4, or 4^3.
If I hear you, correctly you read that it's:
If I get 39 Str, that multiplies by x4.
If I get 49 Str, that multiplies by x4*2 = x8.
If I get 59 Str, that multiplies by x4*3 = x12.
That's what you're getting, right?
For clarity, it doesn't have to be 29; rather it can be any strength between 20 and 29 that increases by 10 that follows this pattern*. That's why I'm looking at the actual multiplier rather than the final number.
* Nevermind that this pattern doesn't hold up at lower numbers. It can seem pretty close from 10->20 (going from 33*4 is 132, while going from 133/4 -> 33.8), but that isn't entirely correct, and it entirely falls apart at numbers below that (as, say, comparing 11 STR and 1 STR; 3x4 = 12, while 38/3 -> 12+(2/3)... nope, not even close).
EDIT: ninja Vid edit!
Edit: My initial impression is that you would figure out the modifier for having a 50 str for example so it would be x8 (4+4) but and I think your right now that I think about it. it would be a 16 (4x4) multiple
Right?
Yeah, I'm getting the latter, by my reading. I guess I can see the former (as it's much easier), but the latter seems to be what they're saying.
That said, I'm prepared to be wrong!
| Tacticslion |
Vid's eventual response (there's a lot of stuff there I'm chopping out, and I'm editing the format, slightly, for clarity):
---- bump for easy reading ----
---- bump ----
---- final bump for phones ----
Tremendous Strength: For Strength scores not shown on Table: Carrying Capacity, find the Strength score between 20 and 29 that has the same number in the "ones" digit as the creature's Strength score does and multiply the numbers in that row by 4 for every 10 points the creature's Strength is above the score for that row.
hmm. I'm leaning towards the 4*2 4*3 4*4 route but i'm still not sure enough to say.
| Tacticslion |
I keep hearing the one punch man theme playing in my head.
Well, he does sound pretty mythic...
That said, as I noted in the other thread, if you go by the multiplication method...
Hmmmm... suddenly this doesn't seem so impossible by rules, after all...
Although the creature's current strength is only 48, that's a pretty good starting base, especially since the origin was millions of foul creatures being pulled within...
... as in, it could have had what amounts to a temporary strength boost that enabled it to claw it's own way out.