Multiclassing math


Rules Questions


So I've got a 16th Level Halfling character who did the following advances: Ninja 4/Dawnflower Dervish 8/Mouser 1/Vexing Dodger 1/Kensai 2

For the life of me, I'm not sure of the math for both his saves & BAB.

Ninja (favored class) 4th: BAB +3, Fort +1, Ref +4, Wil +1
Dervish 8th: BAB +6/+1, Fort +2, Ref +6, Wil +6
Swashbuckler (Mouser) 1st: BAB +1, Ref +2
Vexing Dodger 1st: Ref +2
Magus (Kensai) 2nd: Fort +3, Will +3

Can anyone- please- help me figure his BAB & saves out? Then maybe even explain the math?


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The Saves are the simplest. You just add them up.

Fortitude = 1 + 2 + 0 + 0 + 3 = +6
Reflex = 4 + 6 + 2 + 2 + 0 = +14
Will = 1 + 6 + 0 + 0 + 3 = +10

For BAB you start by adding up the first value listed for each class. So for your Dervish levels use the +6 and ignore the +1. (You left off the +1 BAB for your Kensei levels, but I've put it in.)

BAB = 3 + 6 + 1 + 0 + 1 = +11

That is for your main attack. Finding the iterative values is slightly trickier. Each iterative has a value which is 5 less than the previous attack, and iteratives require a value of at least +1 to exist.

So your first attack is at a +11 value. Subtracting 5 produces an iterative at +6. Subtracting 5 more produces an iterative at +1. Subtracting 5 more produces a value of -4 which is too low. So you have three attacks and your BAB is written as +11/+6/+1.

A different way of looking at the iteratives is that each time your weakest attack reaches +6 you add a new iterative with a value of +1. This is easiest to see using a full BAB progression table like the one for the Fighter. Notice that they get a new +1 iterative at levels 6, 11, and 16. That is when the previously lowest iterative has reached +6.

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