Single location scenario, all random AD5 & 6 Henchmen. Theoretically, it's possible -and even likely- that *both* HH and IM are shuffled in, AND that HH is above IM. Then, HH says:
"BYA, summon and defeat Inger- Maggor, or Herald's Heart is undefeated."
In the above setup - does that mean I CANNOT defeat HH until the deck is shuffled an Inger is on top, defeat and sent to the box - so he can finally be summoned when HH comes around again?
It would seem so by the rules, but we hope someone can come up with a reason otherwise...
It looks like you are correct by RAW, and it creates a potential dilemma. I see two alternatives to resolve this.
First, you can just leave Herald's Heart out (so not truly "all random AD 5 & 6 Henchmen").
Second, you can leave Inger-Maggor out so that you can summon him if/when you encounter Herald's Heart.
From a storyline perspective, the Herald's Heart is no longer a separate entity (part of winning the last scenario in AD 5), so it doesn't make sense that you would face it again. I recommend the first alternative.
If that were to ever become an official resolution, it would be something along the lines of the Justifiable Deicide card being changed to:
HENCHMEN
RANDOM HENCHMEN THAT HAVE AN ADVENTURE DECK NUMBER OF 5 OR HIGHER, EXCEPT HERALD'S HEART.
I think this would fall under the "ignore impossible instructions" rule. If summoning is impossible, you ignore any consequences of the summoning. So, Herald's Heart is not undefeated, and you continue on with the encounter.
I think this would fall under the "ignore impossible instructions" rule. If summoning is impossible, you ignore any consequences of the summoning. So, Herald's Heart is not undefeated, and you continue on with the encounter.
I think that's a fairly common-sense interpretation and probably what I'd actually do*, but I don't think it's technically correct. The only part that's impossible is the summon (and by extension defeat) part, the "is undefeated" part is still possible and I can't see a good technical reason why it wouldn't happen. It kind of reminds me of that case where you have to summon and defeat a random barrier and get one with no check to defeat.
* actually what I would do in practice is find the relevant stats for Inner-Maggot (oh, look, there they are) and just encounter it anyway.