Spoiler alert: This deals with the "Here Comes the Flood" scenario.
When my group played through the flood scenario, where you have to save more allies than the snake eats, once we knew we had saved enough that we were guaranteed victory, we didn't bother to save others that we knew about but didn't want for our decks.
We knew there were 15 allies, and you have to save at least as many as the snake eats. We rescued 7, then on the 8th we didn't bother saving him, we just let him go back to the box because we were guaranteed victory whether we saved him or not. We also used Harsk to find another. We didn't want him for our deck so we let the snake eat him because we had already guaranteed victory.
I think it was weird to have a guaranteed victory without the scenario ending. I also don't like how we could just not bother saving people and still have the guaranteed win.
The scenario calls for shuffling X henchmen, X blessings, and X allies together, where X is the number of locations, and then giving 3 to each location. This guaranteed we know the exact ally count.
So I propose a slight change. Start by shuffling 2X allies and 2X blessings together, giving you a pile of 4X cards. Take half of these (2X) and shuffle them together with X henchmen and then give 3 to each location.
This will give the same probability distribution of allies and blessings, but with the added effect that you will not know how many allies there are exactly. Even if you give out more or less allies than normal, it still doesn't change the difficulty. With less allies you find and rescue less, but the snake also eats less. With more allies you find and rescue more, but the snake eats more.
So this just makes it so you don't know how many allies there are, so you have to keep trying to save them throughout the whole scenario, without altering the mechanics of the fight or making it any easier or harder. Do other people like this idea, or am I alone in thinking this is an easy improvement.
