Marnay Zyrvana

pepsi the voice of a new generation's page

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Will you publish material for Modiphius' Conan game?

@media queries are the bomb.

In my web development class, I'm learning how HTML, CSS, JS work together inside a dynamic website to create magic.
Or maybe it's magic to begin with and the division into categories of HTML, CSS, JS is merely how our human mind grasps it.

We all change our passwords on a regular basis.
What was one of your favorite old passwords you can't use any longer?

//shneck master here. drop one five biscuits. roger ranger.

n starts at 0.
So, compute a(0) quickly followed by a(1).
Now we have a(1), so compute a(2).

I don't see why this is so difficult. That means I'm missing something.


Tonight's endevour... make (a(n-1),a(n)) |--> (a(n),a(n)) work. I think work is the correct word.

I'm back again for a few hours. It's near 1am and I study best in the dark.
Now the sun is asleep, and malevolent entities forage in the night hunting for knowledge. Or perhaps they are more pernicious and seek to prey on humans lost in the darkness. To find one in its grasp, and eat the still warm brain.

"Run", she screams.

Black legs scramble across the ground. There are too many legs for the creature to be normal. The guttural voice sounding more like a coughing bull proves it not to be.

"D... Die," it booms out.

James goes down underneath it. He probably never heard her scream. Now her hands are shaking with fear and adrenaline as she tries to fire up a ' javascript' editor.

The light of the editor showed life in her face.

"Code", she thought. "Write code."

Only code will defeat this beast from the dark.

note: this is called procrastination ...

And then the band started playing. So in response, teacherMan asked this question next.

2. Consider the dynamical system

a(n+1) = 2a(n) - 0.25a²(n) - 0.75

The two equilibrium values are a = 1, which is unstable, and a = 3, which is stable. Sketch a cobweb for this equation and use it to determine the maximum interval containing a = 3 such that if a(0) is in this interval, then lim_{k \to infinity} a(k) = 3.

I'm using colored pencils because they're nice.

I got:

a(n) = (4/5)*a(n-1) + 10
a(0) = 20

a0 = 20;
a1 = (4/5)*a0+10 = 26
a2 = (4/5)*a1+10 = 30.8
a3 = (4/5)*a2+10 = 34.64

At 12hrs, dye amount = 34.64mL. Because n steps off 4-hour segments.

Oh, we're using javascript in this class. This doesn't bother me, and .js is so available my opinion is positive.

a = 50

(I graphed it by hand.)

Here is a much older version of my text book. I offer it as a way to play along at home.

Now we are doing starter walkthrough code to numerically walk the "cobb web" and find equilibriums. At least that's what I was told would happen.

A most interesting quiz is going around -- you score if you remember how you died in your most recent past life.

Anyone, can anyone remember?


Think one of those questions is defective.

Those ancient clothe makers didn't play around:

1. Suppose a bowl contains five cups of water. Initially, add 20 ml of die to the bowl. Then every 4 hours, replace one cup of water with a cup of water containing 10 ml of dye.
- a. Develop a dynamical system for a(n), the amount of dye in the bowl after n four-hour time periods.
- b. How much dye will be in the bowl at the end of 12 hours?
- c. What is the equilibrium value for this dynamical system?
- d. Sketch a cobweb diagram for this problem.

And now the fun began:

Distant Scholar wrote:
Who are "they" that are asking you? I can't attempt to explain "why" without knowing "who".

I'm taking this man's modeling class.

Yesterday he said this equation pertains to an ancient type of analysis named cobb web analysis. He handed out a short tome on the subject and, get this, it's partially written in sanskrit.

I'm in a computer science class so I was a bit surprised, and last night was hunting around for some insight. A bit of background, he said hindu scribes from around 300 AD first discovered this type of analysis and used it while mixing dye for producing colored clothe. And now here I am learning about it in Modeling 1 class.

y = 0.75x
This is the equation of a line with slope m=0.75.
The corresponding inputs and outputs for this line (16,12), (12,9), (9,6.75), ...

How do we get from one point to the next? In particular, how can the point (a(1),a(2)) = (12,9) be used to find the next point (a(2),a(3)) = (9,6,75)?

Is there a smart gamer who can explain why they're asking me this?